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AIC 1st Term Maths Exam for SS 1
  • 1. Convert 37 in base ten to base five
A) 1001011
B) 1225
C) 122
D) 1023
  • 2. Convert 1264 in base eight to base ten
A) 117
B) 692
C) 171
D) 629
  • 3. Convert 211 in base three to base eight
A) 62
B) 11
C) 7
D) 26
  • 4. Convert 1.101 to decimal
A) 1.625
B) 0.125
C) 0.25
D) 0.625
  • 5. In what base is the addition 465 + 24 + 225 = 1050?
A) 5
B) 7
C) 9
D) 6
  • 6. Evaluate (203)2 in base four
A) 103021
B) 11512
C) 10152
D) 113021
  • 7. Evaluate 11110 ÷ 110
A) 1100
B) 101
C) 110
D) 1011
  • 8. If (34) in base five = 23x, find x.
A) x = 16
B) x = -16
C) x = -8
D) x = 8
  • 9. Round off 163.864 to the nearest whole number
A) 163
B) 164
C) 163.9
D) 200
  • 10. Express the sum of 6.03 x 106 and 2.17 x105 in standard form
A) 6.247 x 1011
B) 6.247 x 10-6
C) 6.247 x 106
D) 6.247 x 10-11
  • 11. Simplify (1/4)-½
A) 21/2
B) 2
C) 2-1/2
D) -2
  • 12. If x is a positive integer, determine the least value of x for which 13 + 2x = 3(mod 8)
A) 3
B) 16
C) 5
D) 1
  • 13. Evaluate 3√350 using logarithm table
A) 7.047
B) 704.7
C) 704700
D) 70.47
  • 14. Evaluate (3.69 x 105) ÷ (1.64 x 10-3)
A) 2.25 x 10-8
B) 2.25 x 10-2
C) 2.25 x 108
D) 2.25x 102
  • 15. Calculate the following using mathematical table. 3√(38.32 x 2.964/8.637 x 6.285)2
A) 0.2137
B) 7.716
C) 1.636
D) 4.1106
  • 16. Express 0.0006131 in standard form
A) 6131 x 104
B) 6131 x 10-4
C) 6.131 x 10-4
D) 6.131 x 104
  • 17. Simplify (1/16)-¾ + 5 (90)
A) 7/25
B) 2/3
C) 3½
D) 13
  • 18. Evaluate 2 ÷ (64/125)-⅔
A) 3 ½
B) 2 ⅛
C) 5 ⅚
D) 1 ⁷/25
  • 19. Simplify 125⅓ x 49½ x 10-1
A) 35/5
B) 2 ⅓
C) 3 ½
D) 6 ⅞
  • 20. Given that 102 = 100, write the expression in logarithm form
A) 3 = log10 100
B) 1 = log10 102
C) 2 = log10 100
D) 100 = log10 2
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